-2x^2+11x+-10=0

Solution for -2x^2+11x+-10=0 equation:

-2x^2+11x+-10=0

We add all the numbers together, and all the variables

-2x^2+11x=0

a = -2; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-2)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-2}=\frac{-22}{-4}
=5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-2}=\frac{0}{-4}
=0
$